TopologyVersionIsFresherThan Method

Gets whether or not x is fresher than y. Comparing topology descriptions freshness does not exhibit the reversal property of inequalities e.g. a.IsFresherThan(b) (a "<" b) does not imply !b.IsFresherThan(a) (b ">" a) See for more information. In the case that this.Equals(y), y will be considered to be fresher.

public static bool IsFresherThan(
	TopologyVersion x,
	TopologyVersion y
)

Public Shared Function IsFresherThan ( 
	x As TopologyVersion,
	y As TopologyVersion
) As Boolean

static member IsFresherThan : 
        x : TopologyVersion * 
        y : TopologyVersion -> bool